Question

line p has an equation of y=1/10x+6. perpendicular to line p is line q, which passes through the point (1,-9). what is the equation it q?​

Answer 1

y = - 10x + 1

Explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y =
`(1)/(10)` x + 6 ← is in slope- intercept form

with slope m =
`(1)/(10)`

Given a line with slope m then the slope of a line perpendicular to it is

`m_(perpendicular)` = -
`(1)/(m)` = -
`(1)/((1)/(10) )` = - 10, thus

y = - 10x + c ← is the partial equation

To find c substitute (1, - 9 ) into the partial equation

- 9 = - 10 + c ⇒ c = - 9 + 10 = 1

y = - 10x + 1 ← equation of line q