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A rock thrown up into the air with an initial speed of 25 m/s . How much time will pass before the rock is moving back down at 6 m/s ?
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A rock thrown up into the air with an initial speed of 25 m/s . How much time will pass before the rock is moving back down at 6 m/s ?

User Remon
by
7.3k points

1 Answer

5 votes
To reach the highest point it will take time t
v= u + at
0 = 25 -9.8t
time t = 25/9.8 = 2.55 seconds

On the way down
v = u + at
6 = 9.8 t

time t= 6/9.8 = 0.61 seconds

Total time = 2.55 + 0.61 = 3.16 seconds
User Pratik Mandrekar
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7.7k points
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