Question

A cyclist is riding a bike with an initial speed of 4 m/s and accelerates uniformly at 2 m second squared in the same direction of its motion along the street what is the speed of the cyclist after traveling 6 m ?

Answer 1

6.32m/s

Step-by-step explanation:

Given parameters:

Initial velocity = 4m/s

Acceleration = 2m/s²

Distance covered = 6m

Unknown:

Final velocity = ?

Solution:

To solve this problem, we have to apply the appropriate motion equation;

V² = U² + 2aS

where V is final speed

U is the initial speed

a is the acceleration

S is the distance

Insert the given parameters and solve;

V² = 4² + 2 x 2 x 6

V² = 16 + 24

V² = 40

V = √40 = 6.32m/s