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X^2 - x + 6 = 0

how do I solve that?​

1 Answer

3 votes

Answer:

no solution

Explanation


x^(2)-x+6=(x^(2)-2.(1)/(2)x+(1)/(4))+6-(1)/(4)=(x-(1)/(2))^(2)+(23)/(4)

see :
(x-(1)/(2))^(2)\geq 0 => (x-(1)/(2))^(2)+(23)/(4)\geq 0+(23)/(4)>0

but x² - x + 6 =0

=> it is unreasonable

User Khemraj
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