Solve the equation for all real solutions. k^2+8k+22=6

Question

asked Apr 20, 2021 133k views

1 Answer

Brian Singh · Answer 1 · 2021-04-25T15:20:32+0000

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${k}^(2) + 8k + 22 = 6$

Subtract sides 6

${k}^(2) + 8k + 22 - 6 = 6 - 6$

${k}^(2) + 8k + 16 = 0$

$({k + 4})^(2) = 0$

Thus ;

k + 4 = 0

Subtract sides 4

k + 4 - 4 = - 4

k = - 4

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