Question

A space shuttle enters Earth’s upper atmosphere with a velocity of 11,200 m/s and experiences an acceleration of -70 m/s². What is the magnitude of the shuttle’s velocity 10 s after the shuttle enters the upper atmosphere?

Answer 1

The magnitude of the shuttle's velocity 10 seconds after it enters the upper atmosphere is 10,500 m/s.

Step-by-step explanation:

To find the magnitude of the shuttle's velocity 10 seconds after it enters the upper atmosphere, we need to use the equation:

v = u + at

where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time. Plugging in the given values:

v = 11,200 m/s - 70 m/s² * 10 s

Simplifying the equation:

v = 11,200 m/s - 700 m/s

v = 10,500 m/s

where v is the final velocity, u is the initial velocity.

Therefore, the magnitude of the shuttle's velocity 10 seconds after it enters the upper atmosphere is 10,500 m/s.

Answer 2

magnitude =

Step-by-step explanation:

Given an initial velocity of 11200m/s, and acceleration of -70m/s^2, we are told to find the magnitude of the velocity in 10s.

In general, magnitude is defined as the numerical value or quantity of a variable. In physics, magnitude refers to the total measure(length) of distance covered.