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What are the solutions to the equation?

x²-12x+36=4
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x1 =
x2=

1 Answer

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The roots of this equation equation are:

x1 = 4

x2 = 8

This sentence given in the statement of this question is: Equation of the Second Degree. There are a few ways to solve it, but let's calculate by the factorization method.

Equation given: x² - 12x + 36 = 4

  • First, let's multiply the 12 and 36 term into factors (factoring):

x² - 12x + 36 = 4

12x ➯ 2x . x6

36 ➯ 6²

x² - 2x . x6 + 6²

( x - 6 )² = 4

  • Now we remove the parentheses and we will transform the exponent 2 into the square root of its original number:

( x - 6 )² = 4

x - 6 = ±√4

x - 6 = ±2

  • We will organize the equation in two forms, being: positive and negative:

x - 6 = ±2

x - 6 = -2

x - 6 = +2

  • Finally, let's calculate the first degree equation:

x - 6 = -2

x = -2 + 6

x = 4

x - 6 = +2

x = 2 + 6

x = 8

Therefore, the correct results of this equation, will be:

x1 = 4

x2 = 8

User Torsten Walter
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