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the prices of stock A at 9am was $12.18 since then the price has been increasing at the rate of $0.06 each hour. At noon the price of stock B was $12.68. It begins to descrease at the rate of $0.09 per hour. If the 2 rates continue in how many hours will the prices of the two stocks be the same?

User Lomefin
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1 Answer

3 votes

Answer:

3.33hours

Explanation:

Where the number of hours = h

the prices of stock A at 9am was $12.18 since then the price has been increasing at the rate of $0.06 each hour.

The Algebraic expression =

$12.18 + $0.06 × h

12.18 + 0.06h

At noon the price of stock B was $12.68. It begins to descrease at the rate of $0.09 per hour.

$12.68 - $0.09×h

12.68 - 0.09h

If the 2 rates continue in how many hours will the prices of the two stocks be the same?

Stock A = Stock B

12.18 + 0.06h = 12.68 - 0.09h

Collect like terms

0.06h + 0.09h = 12.68 - 12.18

0.15h = 0.5

h = 0.5/0.15

h = 3.3333333333 hours

h = 3.33hours

User Miasia
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