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What product is formed when each compound is treated with either LiAlH4 (followed by H2O), or NaBH4 in CH3OH

1 Answer

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The missing diagrams are shown in the diagrams attached below.

Answer:

Step-by-step explanation:

The reaction of Lithium Aluminium hydride LiAlH4 with Alkanone leads to the formation of secondary alcohol products. This is because Lithium Aluminium hydride LiAlH4 acts as a reducing agent. The reaction of NaBH4 in CH3OH with Alkanone is less reactive as compared with Lithium Aluminium hydride LiAlH4, thus it also reduces aldehydes and ketones. From the image attached below, we will see the missing diagram and the mechanism used in the process for the formation of those products.

What product is formed when each compound is treated with either LiAlH4 (followed-example-1
What product is formed when each compound is treated with either LiAlH4 (followed-example-2
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