Answer:
The average reactive power is
![I_(rms)V_(rms) cos \phi](https://img.qammunity.org/2021/formulas/engineering/college/od10oy0sfmasaomydv6tbcwlymp383bxm6.png)
Step-by-step explanation:
For a single-phase AC circuit;
the peak current in the circuit is given as
![I_o](https://img.qammunity.org/2021/formulas/physics/high-school/rbt6izheqgm3jvq3pgm6gqscvoszezq8vs.png)
the root-mean-square current is given by;
![I_(rms) = (I_o)/(√(2))](https://img.qammunity.org/2021/formulas/engineering/college/l2ac3kesjfp1jvhg9kgm4xp765msafh9rn.png)
the peak voltage in the circuit is given as
![V_o](https://img.qammunity.org/2021/formulas/physics/high-school/et1084pn5ua113h7oc3zzlugpt55d3c39k.png)
the root-mean-square voltage is given by;
![V_(rms) = (V_o)/(√(2) )](https://img.qammunity.org/2021/formulas/engineering/college/agkvax311dbib555aynnf9n2ef8hrjlozt.png)
The average reactive power is given by
![P_(avg) = I_(rms)V_(rms) cos \phi](https://img.qammunity.org/2021/formulas/engineering/college/fcn7kw9hq4h8lzrx7x9k5jgjb1y3c1xehe.png)
where;
![cos \phi \ is \ the \ power \ factor](https://img.qammunity.org/2021/formulas/engineering/college/vlpsza7okcytsk29ov0pu9ysomxrvyevc7.png)
Therefore, the average reactive power is
![I_(rms)V_(rms) cos \phi](https://img.qammunity.org/2021/formulas/engineering/college/od10oy0sfmasaomydv6tbcwlymp383bxm6.png)