Question

The line passes through points A (6:0) and B(O:4). Write the equation of the line.​

Answer 1

y = (-2/3)x + 4 or

3y = -2x + 12

Explanation:

Slope of line passing through (x₁, y₁) and (x₂, y₂) is given by

`(y_(2) - y_(1))/(x_(2) - x_(1))`

In this particular case where the points are (6,0) and (0,4) we get the slope as (4-0)/(0-6) = -2/3

Equation of a line with slope m and y intercept c is given by

y = mx + c

substituting for m we get the equation y = (-2/3)x + c

Substituting the first point (6,0) we get

0 = (-2/3)(6) + c or -4 + c = 0 or c =4

Therefore y = (-2/3)x + 4 or multiplying both sides by 3 we get

3y = -2x + 12