Answer:
![x = 20](https://img.qammunity.org/2021/formulas/mathematics/middle-school/q1i7dn6ljir99re9fojnl8jwj6cyxusu19.png)
Explanation:
The question is different from the attachment.
The question itself can not be solved without the right attachment.
So, my answer will be based on the attachment
Given
![m_3 = 5x + 10](https://img.qammunity.org/2021/formulas/mathematics/college/xtzv81iyyq0pz9sm1ahydm1ypodficqydc.png)
![m_5 = 3x + 10](https://img.qammunity.org/2021/formulas/mathematics/college/cc7cgj630ix4rj8zl01rz8707eimivfyiq.png)
Required
Find x
m3 and m5 are supplementary. The relationship between than can be written as:
![m_3 + m_5 = 180](https://img.qammunity.org/2021/formulas/mathematics/college/fzr5h8qj12fxmnxt1imhcabfv5a53kptct.png)
This gives
![5x + 10 + 3x + 10 = 180](https://img.qammunity.org/2021/formulas/mathematics/college/ekqvovuzlll79b14ey46668r2glirldwtp.png)
Collect Like Terms
![5x + 3x = 180 - 10 -10](https://img.qammunity.org/2021/formulas/mathematics/college/fna9jdxtutwmpu6m546xo3m5kc4byapcwx.png)
![8x = 160](https://img.qammunity.org/2021/formulas/mathematics/college/u4p9zaa2zss33jt6ytu3tts3udi6b77xwm.png)
Solve for x
![x = 160/8](https://img.qammunity.org/2021/formulas/mathematics/college/h8964q53z0snf9dlyf0ocyrejp8y5nxnkg.png)
![x = 20](https://img.qammunity.org/2021/formulas/mathematics/middle-school/q1i7dn6ljir99re9fojnl8jwj6cyxusu19.png)