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45 votes
45 votes
How many solutions exist for each system of equations?
x + 2y = –1
2x + 3y = 0

User Dchar
by
2.9k points

1 Answer

6 votes
6 votes

Answer:

2 solutions x = 3 y = -2.

Explanation:

x + 2y = –1

2x + 3y = 0

Multiply first equation by -2:

-2x - 4y = 2 Adding this to second equation:

- y = 2

y = -2.

Plug this into first equation:

x - 4 = -1

x = 3.

User Shahnur
by
2.6k points