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What is the slope of a line that is perpendicular to the line 3y - 4x = -8?

User Kimora
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1 Answer

1 vote

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3y - 4x = - 8

Add sides 4x


3y - 4x + 4x = 4x - 8


3y = 4x - 8

Divide sides by 3


(3)/(3) y = (4)/(3) x - (8)/(3) \\


y = (4)/(3) x - 8 \\

This is the slope-intercept form of the line.

We that the coefficient of the x in slope-intercept form , is the slope of the line.

Thus ;


slope = (4)/(3) \\

_________________________________

Remember from now on ;

Multiply of the slopes of the lines which are perpendicular to each other equal -1 .

Suppose the slope of the line which question asked is m.

So :


(3)/(4) * m = - 1 \\

Multiply sides by 4


4 * (3)/(4) * m = 4 * ( - 1) \\


3m = - 4

Divide sides by 3


(3)/(3) m = ( - 4)/(3) \\


m = - (4)/(3) \\

Done...

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User Deshanna
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