Question

How many grams of Al are needed to react with 91.8 grams of FeO
3FeO + 2Al —> 3 Fe +Al2O3

Answer 1

Ans : 22.86 gm of Aluminium

Solution,

3FeO + 2Al ---> 3 Fe +
`Al_(2)O_(3)`

Given 3 2

Find 1.27 x

By the given gms of FeO find its mole and put the moles in the find,

`n = (given mass)/(molecular mass)`

Given mass of FeO is 91.8

Molecular mass of FeO is 71.8

n =
`(91.8)/(71.8)`

n = 1.27 moles of FeO

Now solve for x,

`x = (2 x 1.27)/(71.8)`

x = 0.85 moles

These are just moles of Aluminium that we need to react with FeO, so to find Grams of Aluminium we need,

Mass = moles x molecular mass

Mass = 0.85 x 27(atomic mass of Al)

Mass = 22.86 grams of aluminium is what we need