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What is the real solution for x^2-6x+9=0

What is the real solution for x^2-6x+9=0
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What is the real solution for x^2-6x+9=0

User Pablo Maurin
by
8.6k points

1 Answer

3 votes

9514 1404 393

Answer:

x = 3

Explanation:

The quadratic expression is a perfect square.

x^2 -6x +9 = 0

(x -3)^2 = 0

x = 3 . . . . . . . . the value of x that makes the factors be zero.

User Celestino
by
8.2k points
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