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What is the solution of the equation x2 + 12x + 23 = 0?

2 Answers

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-13 i think tell me if I’m wrong
User Rmh
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5.0k points
2 votes

Answer: −

sqrt of -13 =−9.606

Step-by-step explanation: Root plot for : y = x2+12x+23

Axis of Symmetry (dashed) {x}={-6.00}

Vertex at {x,y} = {-6.00,-13.00}

x -Intercepts (Roots) :

Root 1 at {x,y} = {-9.61, 0.00}

Root 2 at {x,y} = {-2.39, 0.00}

Solving x2+12x+23 = 0 by the Quadratic Formula .

According to the Quadratic Formula, x , the solution for Ax2+Bx+C = 0 , where A, B and C are numbers, often called coefficients, is given by :

- B ± √ B2-4AC

x = ————————

2A

In our case, A = 1

B = 12

C = 23

Accordingly, B2 - 4AC =

144 - 92 =

52

Applying the quadratic formula :

-12 ± √ 52

x = ——————

2

Can √ 52 be simplified ?

Yes! The prime factorization of 52 is

2•2•13

To be able to remove something from under the radical, there have to be 2 instances of it (because we are taking a square i.e. second root).

√ 52 = √ 2•2•13 =

± 2 • √ 13

√ 13 , rounded to 4 decimal digits, is 3.6056

So now we are looking at:

x = ( -12 ± 2 • 3.606 ) / 2

Two real solutions:

x =(-12+√52)/2=-6+√ 13 = -2.394

or:

x =(-12-√52)/2=-6-√ 13 = -9.606

User Bobby S
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4.9k points