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Write the sides of ∆ABC in order from LONGEST to SHORTEST if m∠A = x² - 18, m∠B = 2x² + 3x, and m∠C = 12x.

User Jay Wit
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1 Answer

7 votes

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Answer:

b, c, a or AC, AB, BC

Explanation:

The sum of the angle measures is 180°, so we have ...

∠A +∠B +∠C = 180°

(x^2 -18) +(2x^2 +3x) +(12x) = 180

3x^2 +15x = 198 . . . . add 18, simplify

x^2 +5x = 66 . . . . . . divide by 3

x^2 +5x -66 = 0 . . . subtract 66 to put in standard form

(x +11)(x -6) = 0 . . . . . factor

Solutions are x = -11, x = 6. Angle C requires x > 0, so the only useful solution is x = 6.

Then the angle measures are ...

∠A = x^2 -18 = 6^2 -18 = 18

∠B = 2x^2 +3x = x(2x +3) = 6(2·6 +3) = 90

∠C = 12x = 12·6 = 72

The angles, largest to smallest are B, C, A. Their opposite sides are in the same order, longest to shortest: b, c, a. Those sides will also be named AC, AB, BC.

User Bep
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8.3k points
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