Question

An electric bulb is labeled 240v, 60w. How much current is taken by the bulb?​

Answer 1

Power of that electric bulb is 60W.

Voltage of that bulb is 240V and we have to calculate the current (I).

• P = 60W
• V = 240V
• I = ?

Now, as we know that electrical power (P) is calculated by the formula :

• P = VI

Here,

• P is power
• V is voltage
• I is current

Substituting the values in the formula,

`\implies \: \sf{60 = (240)(I)}`

`\implies \: \sf{60 = (240) * (I)}`

`\implies \: \sf{I \: = \: (60)/(240) }`

`\implies \: \sf{I \: = \: \cancel(60)/(240) }`

`\implies \: \sf{I \: = \: (6)/(24) }`

`\implies \: \sf{I \: = \: \cancel(6)/(24) }`

`\implies \: \sf{I \: = \: (3)/(12) }`

`\implies \: \sf{I \: = \: \cancel(3)/(12) }`

`\implies \: \sf{I \: = \: (1)/(4) }`

`\implies \: \sf{I \: = \: \cancel(1)/(4) }`

`\implies \: \red{\bf{I \: = \:0.4A}}`

Answer 2

Current = 0.25 A

Further explanation

Electric power i: electrical energy per unit time

`\tt P=(W)/(t)`

P = watt

W = electrical energy, J

t = time, s

or

P = V.I

V=voltages, volt

I=current,A

An electric bulb is labeled 240v, 60w,

So,

P = 60 watt

V=240 volt

`\tt I=(P)/(V)\\\\I=(60)/(240)=0.25~A`