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75 g of a metal is heated to a temperature of 99C. The metal is then placed in a calorimeter containing 145 g of water at a temperature of 25C. The temperature of the water in the calorimeter increase to a final temperature of 28C. What is the specific heat of the metal?

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Answer:

0.34 J / g ⁰C

Step-by-step explanation:

Let the specific heat of metal be s .

heat will be lost by hot metal and gained by water .

heat lost by metal = mass x specific heat x loss of temperature

= 75 x s x ( 99 - 28 ) = 5325 s

heat gained by water = mass x specific heat x gain of temperature

= 145 x 4.18 x ( 28 - 25 ) = 1818.3

heat lost = heat gained

5325 s = 1818.3

s = 0.34 J / g ⁰C

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