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A submarine is exploring the Pacific Ocean. At 502.5 feet below sea level, the water temperature is 63 1/4 °F. The submarine dives down 115 feet deeper, and the water temperature drops by 2 1/5°F. What were the elevation and the water temperature after the submarine dove? Assume that sea level is at 0 feet of elevation.

Find the water temperature after the submarine’s final dive in decimal form. Show your work.

User Leetom
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2 Answers

6 votes

Answer:

61 1/20 °F

Explanation:

User FarFarAway
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4.9k points
6 votes

Answer:

At the elevation 617.5 feet below the sea level temperature of the water was 61 1/20 °F

Explanation:

At 502.5 feet below the sea level temperature of the water is 63 ¼ °F

When submarine dives down 115 feet deeper, water temperature drops by 2 ⅕ °F

Elevation after the submarine dove = -502.5 - 115 = -617.5 feet

This negative sign represents the elevation below the sea level.

And the temperature will be = 63 ¼ - 2 ⅕

= 253/4 - 11/5

= 1,265-44/20

= 1,221/20

= 61 1/20 °F

Therefore, at the elevation 617.5 feet below the sea level temperature of the water was 61 1/20 °F

User Harathi
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