Question

What mass, in milligrams, of carbon tetrachloride is present in a 55 gallon drum of the substance?

Density of carbon tetrachloride is 1.492 g/mL. *Remember you have a conversion factor sheet and metric notes as well

Answer 1

310630745 mg or 3.11×10⁸ mg

Step-by-step explanation:

From the question given above, the following data were obtained:

Volume = 55 gallon

Density = 1.492 g/mL.

Mass =?

Next, we convert 55 gallon to mL. This can be obtained as follow:

1 gallon = 3785.41 mL

Therefore,

55 gallon = 55 gallon × 3785.41 mL / 1 gallon

55 gallon = 208197.55 mL

Thus, 55 gallon is equivalent to 208197.55 mL.

Next, we shall determine the mass as follow:

Volume = 208197.55 mL.

Density = 1.492 g/mL.

Mass =?

Density = mass /volume

1.492 = mass /208197.55

Cross multiply

Mass = 1.492 × 208197.55

Mass = 310630.745 g

Finally, we shall convert 310630.745 g to milligrams (mg) as follow:

1 g = 1000 mg

Therefore,

310630.745 g = 310630.745 g × 1000 mg / 1 g

310630.745 g = 310630745 mg

310630.745 g = 3.11×10⁸ mg

Therefore, the mass of carbon tetrachloride in mg is 310630745 mg or 3.11×10⁸ mg