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6 votes
And also this q plsss the deadline is tmrw i have no time

And also this q plsss the deadline is tmrw i have no time-example-1
And also this q plsss the deadline is tmrw i have no time-example-1
And also this q plsss the deadline is tmrw i have no time-example-2

2 Answers

13 votes

Answer:

Okay so you basically need to break this shape into sensible pieces. Such as rectangular and triangular prisms.

first let's find the rectangular prisms' volume, we need to multiply 6.5 with 10 and 8.

6.5×10×8 gives us 520

520 is the volume of the rectangular prism (below the shape)

to find the triangular prism's volume follow these steps:

2.5×8×10×1/2 which gives us 100

now we need to take the sum of these

100+520=620

the answer is C good luck!

User NewKidOnTheBlock
by
4.6k points
5 votes

Problem 8

The box portion of the shed (ignoring the triangular roof) has a volume of:

length*width*height = 10*8*6.5 = 520 cubic feet

The triangular face on the right side has an area of base*height/2 = 8*2.5/2 = 10. Multiply this with the depth of the triangular prism and we get a volume of 10*10 = 100 cubic feet.

The two sub-volumes combine to 520+100 = 620

Answer: 620 cubic feet

===========================================================

Problem 9

Let's find the area of the base

area = side*side = (4.2)*(4.2) = 17.64 sq inches

Then we plug that into the formula below, along with the height of the pyramid

V = volume of a pyramid

V = (1/3)*(area of the base)*(height)

V = (1/3)*(17.64)*(5)

V = 29.4

Answer: 29.4 cubic inches

Your teacher made a typo. She or he should have written
\text{in}^3 instead of
\text{in}^2

User Shubhendu
by
4.1k points