Answer:
This problem can be solved through the creation of a system of equations relating the number of hamburgers (x) and cheeseburgers (y).
Having a combined total of 603 hamburgers and cheeseburgers can be written as x+y=603 and having 53 more cheeseburgers than hamburgers can be written algebraically as y=x+53.
To solve the system:
x+y=603
y=x+53
Substitute what y equals in the second equation for y in the first equation:
x+(x+53)=603
2x+53=603
-53 -53
2x=550
2 2
x=275 hamburgers
To solve for the number of cheeseburgers, substitute 275 for x in either equation.
y=x+53
y=275+53
y=328 cheeseburgers
To double check your work, make sure that 275+328=603 and that 328=275+53. Since both are true, you have solved for the number of hamburgers (275) and cheeseburgers (328).
Explanation: