Question

Which equation is graphed here?

y−1=−13(x−1)

y−1=−13(x+1)

y+4=3(x−1)

y−4=−3(x+1)
Number graph ranging from negative four to four on the x and y axes. A line is drawn on the graph that passes through (negative one, four) and (one, negative two).

Answer 1

Answer: Choice D

y-4 = -3(x+1)

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Step-by-step explanation:

Let's first find the slope of the line through (-1,4) and (1,-2)

`(x_1,y_1) = (-1,4) \text{ and } (x_2,y_2) = (1,-2)\\\\m = (y_(2) - y_(1))/(x_(2) - x_(1))\\\\m = (-2 - 4)/(1 - (-1))\\\\m = (-2 - 4)/(1 + 1)\\\\m = (-6)/(2)\\\\m = -3\\\\`

The slope is -3, which tells us that the answer must be choice D.

Choices A,B, & C can be eliminated because choices A and B have a slope of -13, while choice C has a slope of 3.

Refer to the point-slope format
`y-y_1 = m(x - x_1)` where m is the slope and
`(x_1,y_1)` is a point the line goes through.