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Pls help me find all missing sides and angles. ;-;

Pls help me find all missing sides and angles. ;-;-example-1

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10 votes

Answer:

see explanation

Explanation:

the sum of the 3 angles in the triangle = 180° , then

∠ BAC + 51° + 90° = 180°

∠ BAC + 141° = 180° ( subtract 141° from both sides )

∠ BAC = 39°

using the tangent ratio in the right triangle

tan51° =
(opposite)/(adjacent ) =
(AC)/(BC) =
(AC)/(12.8) ( multiply both sides by 12.8 )

12.8 × tan51° = AC , then

AC ≈ 15.8 ( to 1 dec. place )

using the cosine ratio in the right triangle

cos51° =
(adjacent)/(hypotenuse) =
(BC)/(AB) =
(12.8)/(AB) ( multiply both sides by AB )

AB × cos51° = 12.8 ( divide both sides by cos51° )

AB =
(12.8)/(cos51) ≈ 20.3 ( to 1 dec. place )

User BenBarnes
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