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Find the equation of a line parallel to -x + y = -5 that passes through the point

(-6,-8).
Oy=x-5
O-x+y=-2
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Oy=-x-2
O-z-y=14

User Serina
by
2.3k points

1 Answer

14 votes
14 votes

Answer:

O -x+y=-2

Explanation:

-x + y = -5

⇔ y = x - 5

a line parallel to y = x - 5 must have the same slope as the line y = x - 5

Then

The equation of the parallel line is of the form : y = x + p

Finding p :

the point (-6,-8) lies on the parallel line means :

-8 = -6 + p

Then

p = -8 + 6 = -2

Finally :

y = x - 2 ⇔ -x + y = -2

User Mansur Ali Koroglu
by
3.2k points