Answer:
by using IDENTITY- (x+a)(x+a)=x^2+(a+b)x+ab
thus,
here x=x
a=4
b=-3
So we can substitute the values in the RHS of the identity,
So we have,
x^2+{4+(-3)}x+4*-3
= x^2+(4-3)x+(-12)
= x^2+1x-12
Okay look at my step by step
Explanation:
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