Answer:
6.75 L
Step-by-step explanation:
The following data were obtained from the question:
Mass of NO = 39.6 g
Pressure (P) = 5.54 atm
Temperature (T) = 72°C
Volume (V) =...?
Next, we shall determine the number of mole in 39.6 g of NO. This is illustrated below:
Mass of NO = 39.6 g
Molar mass of NO = 14 + 16 = 30 g/mol
Mole of NO =..?
Mole = mass /Molar mass
Mole of NO = 39.6 /30
Mole of NO = 1.32 moles
Next, we shall convert 72°C to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
Temperature (T) = 72°C
Temperature (T) = 72°C + 273
Temperature (T) = 345 K
Finally, we shall determine the Volume occupied by NO as follow:
Pressure (P) = 5.54 atm
Temperature (T) = 345 K
Number of mole (n) = 1.32 moles
Gas constant (R) = 0.0821 atm.L/Kmol
Volume (V) =...?
PV =nRT
5.54 × V = 1.32 × 0.0821 × 345
5.54 × V = 37.38834
Divide both side by 5.54
V = 37.38834 / 5.54
V = 6.75 L
Therefore, the volume occupied by 39.6 g of NO is 6.75 L