Answer:
S has n linearly independent rows, but not all the rows are independent.
Explanation:
From the information provided:
Let A be an ( n × m ) matrix, and the stacked matrix is defined by:
![S = \left[\begin{array}{c}A&\\I\end{array}\right]](https://img.qammunity.org/2021/formulas/mathematics/college/pkmns09jxv1fui1yo524xslweqzjocvxbf.png)
Then I will be ( n × n) matrix.
So, S will have m + n integers in the row and n integers in the column.
Hence, S must be (m + n) n matrix
From the matrix; we can posit that S has n linearly independent column vectors and n linearly independent rows.
Similarly, 'I' have n linearly independent rows.
{ row vector of S} = { row vector of I} U { row vector of A}
Therefore, S has n linearly independent rows, but not all the rows are independent.