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Ark. (iv). 2(x-3)-3(5x-2) ≤ 6(3-2x)


2( * - 3) - 3(5 * - 2) \leqslant 6(3 - 2x)


User ShiningRay
by
6.0k points

1 Answer

11 votes

Answer:

x ≥ 18

Explanation:

2(x-3)-3(5x-2) ≤ 6(3-2x)

⇔ 2x - 6 - 15x + 6 ≤ 18 - 12x

⇔ 2x - 15x ≤ 18 - 12x

⇔ -13x ≤ 18 - 12x

⇔ -13x + 12x ≤ 18

⇔ -x ≤ 18

⇔ x ≥ 18

⇔ x∈[18 , ∞)

User Vitality
by
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