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2 votes
PLEASE HELP!!!!

A device in your school lab releases gas at a rate of 02.5 liter, which means 0.25 of a liter of gas is released every second.
The density of the gas is from which means that there are 4.3 grams of the gas in one liter. Set up the calculation to
find the number of seconds it will take for the device to release 154 grams of the gas.
Drag each tile to the correct location. The tiles can be used more than once.
S
154 g x

PLEASE HELP!!!! A device in your school lab releases gas at a rate of 02.5 liter, which-example-1
User Kamisha
by
7.1k points

2 Answers

3 votes

Answer: The number of seconds it will take is 143.25 seconds.The formula is s=g/1.075

Explanation:

Given that the rate of gas release is 0.25 liter every second.This means;

1 second= 0.25 liter released

Also;

4.3 grams of gas equals 1 liter

This means;

4.3 grams = 1 liter

So for 154 grams, find the number of liters

=154/4.3= 35.81 liters

But you know;

0.25 liters = 1 second

35.81 liters=?

Cross multiply

(35.81*1)/0.25 =143.25 seconds

Let g be the grams of the gas, and l be the liters of the gas, then to get l you divide g by 4.3. This given you the formula;

l=g/4.3

Let s be the seconds it take for a gas device to release l liters of gas, so to get s you divide l by 0.25. This will be;

s=l/0.25 = (g/4.3) / 0.25

This simplifies to;

s= g/(4.3*0.25)

s=g/1.075

User Waaghals
by
6.6k points
3 votes

Answer:

1.54g* 1 L

over

4.3 G (the 1 and L our 2 boxes and the 4.3 and G is two boxes)

times

1/0.25

S/L

Explanation:

User LoukasPap
by
6.6k points
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