280,696 views
24 votes
24 votes
There were 16 teams that competed in men's ice hockey at the Salt Lake City Olympics of 2002.

Find the number of permutations for the gold, silver, and bronze metals at the awards ceremony.

User Corey Quillen
by
2.9k points

2 Answers

24 votes
24 votes

Answer:

3360.

Explanation:

That would be the number of permutations of 3 from 16.

= 16P3

= 16!/(16-3)!

= 16*15*14

= 3360

User Teukkam
by
2.9k points
9 votes
9 votes

Answer:

3 360 permutations

Explanation:

the number of permutations :

16P3 = 16 × 15 × 14 = 3 360

There were 16 teams that competed in men's ice hockey at the Salt Lake City Olympics-example-1
User Yakov Galka
by
2.9k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.