Question

three charges are located at 100m intervals along a horizontal line: a charge of -3.0C on the left, 2.0C in the middle, and 1.0C on the right. What is the resultant force on the 1.0C charge due to the other two

Answer 1

We know, force is given by :

`F=(kq_1q_2)/(r^2)`

Here, k in a constant.

`Net \ Force = F_1+F_2\\\\Net \ Force = k((Qq_1)/(r_1^2)+(Qq_2)/(r_2^2))\\\\Net \ Force = k( (-3)/(50)+(2)/(50))\\\\Net \ Force = 9* 10^9* (-1)/(50)\ N\\\\Net\ Force = -1.8* 10^8\ N`

Hence, this is the required solution.