Question

In a partially diploid F′ exconjugant, there are two alleles for lac (1 and 2) and two alleles for his (3 and 4). The phenotype of this cell is identical to a lac 1 his 4 cell. What is the best interpretation?

Answer 1

Step-by-step explanation:

Lac 1 and his 4 that shows identical phenotype are wild types.

Wild types are the native, the original species or individual of a particular habitat or colony.

Since lac 1 and his 4 are the wild type, lac 2 and his 3 shares the phenotype of Lac 1 and his 4 this because a cross with a wild type will give an individual with a blend of the two gene with phenotype as the wild because they have a dominant gene.

Lac 1 will shows its phenotype when his 4 is also present this is because a cross between the two will give an individual that is phenotypically identical with the parents

Lac 1 and his 4 are dominant.