Question

What must the magnitude of the magnetic field be in order to produce a flux of 4.50×10−4 WbWb through the surface? Express your answer with the appropriate units.

Answer 1

Complete Question

A horizontal rectangular surface has dimensions 2.50 cm by 3.50 cm and is in a uniform magnetic field that is directed at an angle of 34.5 degree above the horizontal.

What must the magnitude of the magnetic field be in order to produce a flux of 4.50×10−4 Wb through the surface? Express your answer with the appropriate units.

Answer:

The value is
`B = 0.908 \ T`

Step-by-step explanation:

From the question we are told that

The dimension of the rectangular surface is
`2.50 \ cm\ (0.025 \ m ) \ by \ 3.5 \ cm\ (0.035 \ m )`

The angle is
`\theta = 34.5 ^o`

The magnetic flux is
`\phi = 4.50* 10^(-4) \ Wb`

Generally the area of the rectangular surface is

`A = 0.025 * 0.035`

=>
`A = 0.000875 \ m^2`

Generally magnetic flux is mathematically represented as

`\phi = B * A cos (90 - \theta)`

So

`4.50* 10^(-4) = B * 0.000875 cos (90 - 34.5)`

=>
`B = (4.50* 10^(-4) )/( 0.000875 cos (90 - 34.5) )`

=>
`B = 0.908 \ T`