Answer:
5.07 years
Step-by-step explanation:
we solve this using kepler's third law
t² is directly proportional to r³
t²/Te² = r³/Re³
t = asteroid in orbital period around the sun
Te = earth's orbital period around the sun
r = orbital period of the asteroid
Re = orbital radius of the earth
t² = 2.95³
t² = 25.67
t = √25.67
T = 5.07 years.
the orbital period T is therefore 5.07 years