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Determine whether the system of linear equations has one and only one solution, infinitely many solutions, or no solution. Find all solutions whenever they exist.

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Determine whether the system of linear equations has one and only one solution, infinitely many solutions, or no solution. Find all solutions whenever they exist.


x - 3y = -10 \ \ \ and \ \ \ 4x +3y = 20

Answer:

This system of linear equations has one solution which is (x, y) = (2,4 )

Explanation:

The first step is to add that two linear equations


x - 3y = -10\cdots (i) \\ 4x + 3y = 20\cdots (ii)\\------\\ 5x \ \ \ \ \ \ \ = 10

=>
x = 2

substituting this into equation i we have


2 - 3y = -10

=>
y = 4

Hence this system of linear equations has one solution which is (x, y) = (2,4 )

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