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Joseph Priestly discovered oxygen in the eighteenth century by using heat to decompose mercury(II) oxide: 45473 How much oxygen is produced from 7.06 × 102 g HgO?

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Answer:

26.08 g

Step-by-step explanation:

The equation of the reaction for the decomposition of mercury(II) oxide is:


2HgO_((s)) \to ^(\Delta) \ 2 Hg_((s))+O_{2{(g})

Number of moles of HgO = mass/molar mass

Number of moles of HgO = 7.06 × 10² g/ 216.59 g/mol

Number of moles of HgO = 3.26 moles

From the above equation, two moles of mercury (II) oxide decompose to produce two moles of mercury and one mole of oxygen.

Thus, the number of moles of O₂ produced = 1/2 × 3.26 moles

the number of moles of O₂ produced = 1.63 moles

The mass of oxygen O₂ produced = 1.63 moles × 16.0 g/moles

The mass of oxygen O₂ produced = 26.08 g

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