Question

g Calculate the speed of a satellite moving in a stable circular orbit about the Earth at a height of 4740 km .

Answer 1

v = 5987.50 m/s

Step-by-step explanation:

We need to find the speed of the speed of a satellite moving in a stable circular orbit about the Earth at a height of 4740 km.

The formula that is used to find it is given by :

`v=\sqrt{(GM)/(r)}`

M is mass of Earth

r is radius of the Earth plus the height of the orbit

r = 4740 km + 6371 km = 11111 km

Putting all the values,

`v=\sqrt{(6.67* 10^(-11)* 5.972* 10^(24))/(11111* 10^3)}\\\\v=5987.50\ m/s`

So, the speed of the satellite is 5987.50 m/s.