Question

What is the total static head pressure loss in psi from a water meter to the highest fixture, which is 2' above the top floor, in a 4 story building with floor-to-floor height of 12 feet

Answer 1

The value is
`P = 21.6 \  psi`

Step-by-step explanation:

From the question we are told that

The height of the highest fixture above the top floor is
`h  =  2 ft`

The floor to floor height is
`d =  12 \  feet`

Generally given that the building is a four story building then that height of the building is

`k =  4 *  12`

=>
`k =  48 \ ft`

Generally the height of the highest fixture is

`H  =  h  + k`

=>
`H  =  2  + 48`

=>
`H  = 50 \ ft`

Generally the pressure loss is mathematically represented as

`P=  \rho  *  g *  H`

Here
`\rho` is the density of water with value
`\rho =  1.940 \  slugs/ft^3`

and g is the acceleration due to gravity with value

`g = 32.174 \  ft/s^2`

=>
`P=  1.940   *  32.174 *  50`

=>
`P=  3121 \ lb/ft^2`

converting to psi

`P = (3121)/(144)`

=>
`P = (3121)/(144)`

=>
`P = 21.6 \  psi`