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In the Centripetal Force lab, imagine you measured a period of 1.31 s for the twirling rubber block when the string was extended to form a radius of 15.3 cm. What was the speed of the rubber block in m
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In the Centripetal Force lab, imagine you measured a period of 1.31 s for the twirling rubber block when the string was extended to form a radius of 15.3 cm. What was the speed of the rubber block in m/s

User Karan Ashar
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1 Answer

4 votes

Answer:

0.117m/s

Step-by-step explanation:

Speed = distance/time

Given

Distance (radius of string) = 15.3cm

Convert to metres

15.3cm = 15.3/100

15.3cm = 0.153m

Period (time) = 1.31s

Substitute into the formula

Speed of the rubber = 0.153/1.31

Speed of the rubber = 0.117m/s

Hence the speed of the rubber block in m/s is 0.117m/s

User OOPer
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