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Lena is putting colored light bulbs into a string of lights. There are green light bulbs, red light bulbs, and yellow light bulbs. How many distinct orders of light bulbs are there if two light bulbs of the same color are considered identical (not distinct)?

User Amenhotep
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1 Answer

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Complete Question

Lena is putting 11 colored light bulbs into a string of lights. There are 3 white light bulbs, 4 yellow light bulbs, and 4 red light bulbs. How many distinct orders of light bulbs are there if two light bulbs of the same color are considered identical (not distinct)?

Answer:

The value is
N = 11550 \ distinct\ orders

Explanation:

The total number of bulbs is
n = 11

The number of white bulbs is
n_w = 3

The number of yellow bulbs is
n_y = 4

The number of red bulbs is
n_r = 4

Generally the number of distinct order of light bulbs there are if two light bulbs of the same color are considered identical is mathematically represented as


N = (n!)/( n_w ! n_y! n_r!)

=>
N = (11!)/( 3 ! 4 ! 4!)

=>
N = (11 * 10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1 )/( 3 * 2 * 1 * 4 * 3* 2 * 1 * 4 * 3* 2 * 1 )

=>
N = 11550 \ distinct\ orders

User Xnake
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