Question

A very long straight wire carries a 13.8-A current eastward, and a second very long straight wire carries a 12.7-A current westward. The wires are parallel to each other and are 20.5 cm apart. Calculate the resulting magnetic force on a 5.68-m length of one of the wires

Answer 1

The resulting magnetic force is 9.712 x 10⁻⁴ N

Step-by-step explanation:

Given;

current in the first wire, I₁ = 13.8 A

current in the second wire, I₂ = 12.7 A

distance between the wires, d = 20.5 cm = 0.205 m

length of the wire, L = 5.68 m

The resulting magnetic force is given by;

`F = (\mu_o I_1I_2L)/(2\pi d) \\\\F = (4\pi *10^(-7)(13.8*12.7) (5.68))/(2\pi (0.205)) \\\\F = 9.712 *10^(-4) \ N`

Therefore, the resulting magnetic force is 9.712 x 10⁻⁴ N.