Answer:1-METHYL CYCLOHEX-2-ENE
Explanation:
When Sodium ethoxide along with ethanol is taken it means Elimination(Dehydrohalogenation)
reaction will happen and an Alkene or Cyclo Alkene will be formed.
so upon reacting sodium ethoxide with ethanol the accessible hydrogen will be removed forming HBR and new product formed will be
1-Methylcyclohex-2-ene.