Hello. This question is incomplete. The full question is:
Calculate the energy required to ionize a hydrogen atom to an excited state where the electron is initially in the n = 5 energy level. Report your answer in kilojoules.
What is the longest wavelength of electromagnetic radiation capable of ionizing this hydrogen atom in an excited state? Report your answer in nanometers.
Answer:
2282 nm
Step-by-step explanation:
You should start this calculation using the formula: E = (-13.6 / n ^ 2) * eV. This formula refers to the amount of energy required in this system, mentioned in the question above.
Replacing the formula with the values presented in the question we have:
E = (13.6 / 25) * 0.544V = (1,602 × 10 ^ -19) * (0.544 × 10 ^ −3) = 8.71 × 10 ^ −23 kJ
Found that result. We must use the formula:
E = hc / λ
λ = hc / E -----> [(6,626 × 10 ^ −34) * (3 × 10 ^ 8)] /(8.71×10^−23) * 10 ^ 3 =
2282 nm