Question

A wound rotor has a synchronous speed of 1200 RPM. The rotor is rotating at a speed of 1075 RPM. What is the percent of rotor slip and what is the frequency of the induced rotor voltage

Answer 1

rotor slip = 10.42 %

Frequency = 6.24hz

Step-by-step explanation:

given data

synchronous speed = 1200 RPM

rotor rotating speed = 1075 RPM

solution

first we get here rotor slip that is

rotor slip = ( synchronous speed - rotor rotating speed ) ÷ synchronous speed .............................1

rotor slip =
`(1200 -1075)/(1200)`

rotor slip = 0.10416

rotor slip = 10.42 %

and

frequency of the induced rotor voltage is

Frequency = rotor slip × 60

Frequency = 10.42 % × 60

Frequency = 6.24hz