Answer:
The 120-pound person expended 499 lb and the 150-pound person expended 592 lb.
Explanation:
The matrix for number of calories expended by people with different weights and using different ways of exercising for 20 minute time periods is:
![X=\left[\begin{array}{cc}107&136\\126&130\\74&85\end{array}\right]](https://img.qammunity.org/2021/formulas/mathematics/high-school/pjsgj35id7oq6anq94netfxjbqgzazmkvw.png)
It is provided that a 120-pound person and a 150-pound person both bicycle for 40 minutes, jog for 10 minutes, and walk for 60 minutes.
Then the matrix for the number of times the exercises are done is:
![Y=\left[\begin{array}{ccc}(40)/(20)&(10)/(20)&(60)/(20)\\\\(40)/(20)&(10)/(20)&(60)/(20)\end{array}\right] =\left[\begin{array}{ccc}2&0.5&3\\2&0.5&3\end{array}\right]](https://img.qammunity.org/2021/formulas/mathematics/high-school/9jm1ojwjcpugrs21qrmvmho2szgz3ck58w.png)
Compute the number of calories expended by a 120-pound person and a 150-pound person as follows:
![YX=\left[\begin{array}{ccc}2&0.5&3\\2&0.5&3\end{array}\right]* \left[\begin{array}{cc}107&136\\126&130\\74&85\end{array}\right]](https://img.qammunity.org/2021/formulas/mathematics/high-school/vl11jickg63smvzyhv7bhdyikbya6grp5r.png)
![=\left[\begin{array}{ccc}(2\cdot107+0.5\cdot 126+3\cdot74)&(2\cdot136+0.5\cdot 130+3\cdot85)\\(2\cdot107+0.5\cdot 126+3\cdot74)&(2\cdot136+0.5\cdot 130+3\cdot85)\end{array}\right]](https://img.qammunity.org/2021/formulas/mathematics/high-school/r07wvggxujsxuwxax4se88l5ymdsa43thj.png)
![=\left[\begin{array}{ccc}499&592\\499&592\end{array}\right]](https://img.qammunity.org/2021/formulas/mathematics/high-school/irszs3t4o84lig6mhwj62hdr7ndblioq67.png)
Thus, the 120-pound person expended 499 lb and the 150-pound person expended 592 lb.