Question

Two long straight wires carry currents perpendicular to the xy plane. One carries a current of IA = 10 A and passes through the point x = 4 cm on the x axis. The second wire has a current of IB = 68 A and passes through the point y = 7 cm on the y axis. What is the magnitude of the resulting magnetic field at the origin? Write your answer in micro-tesla.

Answer 1

20 * 10^-7 Tesla

Step-by-step explanation:

Given Data:

Wire A passes through ( 4, 0 ) and has a current (i1) = 10 A

distance from origin ( r1 ) = 4

Wire B passes through ( 0 , 7 ) and has a current of 68A

distance from origin ( r2 ) = 7

The magnitude of the resulting magnetic field at the origin

Bnet = B1 + B2

Magnitude of Bnet =
`\sqrt{B_(1) ^(2) } + B^(2) _(2)`

Attached below is the detailed solution