A sample of size 49 is randomly selected from a population with a mean, 25 and standard deviation, 14. Find P(X-bar > 26)

Question

asked Sep 14, 2021 200k views

1 Answer

Jsta · Answer 1 · 2021-09-19T05:52:59+0000

Answer:

P(X>26)=0.4721

Explanation:

$Mean = \mu = 25$

Standard deviation =
$\sigma = 14$

No. of observations = n = 49

We are supposed to find
$P(\bar{X} > 26)$

$Z = (x-\mu)/(\sigma)\\Z=(26-25)/(14)\\Z=0.0714$

Refer the Z table for p value

P(X<26)=0.5279

P(X>26)=1-P(X<26)=1-0.5279=0.4721

Hence P(X>26)=0.4721